A Latin Monetary Union 10 Francs (Gold) contains 0.0933 troy oz of pure gold, worth $373.07 at today's spot price.
Members of the Latin Monetary Union struck the 10 Francs gold coin from 1865 to 1926 in 90% gold. Each coin weighs 3.226 g and holds 0.0933 troy oz (2.903 g) of pure gold. The franc was also used in Algeria, Austria, Belgian Congo, Belgium, Cambodia, Cameroon and other countries.
Melt values use these spot prices (US dollars):
- Gold $3,996.90 per troy oz Current quote · Quote time Oct 24, 12:19 AM EDT
Some prices could not be refreshed recently and may be out of date.
Melt value is the metal content at spot price, not a buy or sell price. Collectible coins can be worth much more. For reference only.
Specifications
| Years | 1865–1926 |
|---|---|
| Face value | 10 Francs |
| Composition | 90% gold |
| Gross weight | 3.226 g |
| Fineness | .900 (90%) |
| Pure metal | 0.0933 troy oz (2.903 g) |
How the melt value is worked out
Melt value is the pure gold in the coin multiplied by the spot price. We use the coin's standard minted weight; worn coins weigh slightly less.
-
3.226 g × .900 fine ÷ 31.1035 g per troy oz = 0.0933 troy oz
0.0933 troy oz × $3,996.90 spot = $373.07
Melt value vs. collector value
Melt value is a floor, not a price. Better dates, coins with mint luster and graded coins often sell well above melt; key dates and rare varieties can be worth many times more. Check the date and mint mark before selling a coin for its metal.